A Detailed Classical
Description
of the Advance of the Perihelion of Mercury.
P. Marmet,
Physics Department,
University of Ottawa, Ottawa, Canada K1N 6N5
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Abstract.
Using
Einstein's
general relativity, it is generally believed that space and time
distortions
are absolutely required to explain the advance of the perihelion of
Mercury.
This is untrue. The advance of the perihelion of Mercury was first
calculated
in 1898 by Paul Gerber (1A).
We show here that this phenomenon can be fully explained using Newton's
physics and mass-energy conservation, without any relativity principle.
Without having to introduce any new physics, we arrive to the same
equation
as predicted by Einstein. Therefore, the relativity principles are
useless.
1-
Introduction.
A
preliminary
classical demonstration of the advance of the perihelion of Mercury has
been given previously in the book: Einstein’s
Theory of Relativity versus Classical Mechanics, (chapters 5 and 6),
[1],without
using any of Einstein's postulates. That demonstration uses
mathematical
relationships, which are based on classical mechanics and mass-energy
conservation.
We explain now in detail, all the physical mechanisms involved in the
calculation
of the advance of the perihelion of Mercury. Using only classical
mechanics,
we obtain the same equation as predicted by Einstein’s General
Relativity,
without using any of the relativity principles. We have seen [1]
that the advance of the perihelion is due to gravitational potential
and
kinetic energy, which modify the standard meter and the clock rate on
Mercury.
The physical change of length and the change of clock rate were
demonstrated
previously [1] . The only
difference between the
usual Newton’s physics and the results presented here is that,
contrarily
to Einstein, we fully take into account the principle of mass-energy
conservation.
This paper shows how to use the units existing on Mercury to derive the
correct shape of the precessing elliptical orbit around the sun.
2-
Orbital
Motion.
An ellipse
with a small eccentricity is identical to a circular orbit, in which
the
center of the circle has been slightly shifted. This can be seen more
easily
when we examine in detail the transformations of shapes from a circle
to
an ellipse. This geometrical transformation is demonstrated in Appendix
1. However, when a circle is slightly perturbed to become an
ellipse,
the change of shape is usually described by the gradual transformation
from a circle to the familiar elongated characteristic shape of an
ellipse.
In the case of the elliptical shape of an orbit around the sun, since
the
eccentricity is small, this is equivalent to a circle with a shifted
center,
because in fact, when adding a small eccentricity, the first
mathematical
term of the series expansion of an ellipse appears as a shift of the
central
circular field of forces. It is only the second term of the
series
expansion of an ellipse, which flattens the orbit into the well-known
elongated
shape (see Appendix1). This
description is useful
for a better understanding of the physics discussed here.
Let us
consider
a mass m orbiting the sun. Newton’s laws show that, due to the
centrifugal
force, when the orbiting velocity is such that the radius of curvature
of the orbiting mass is compatible with distance of a circular orbit
around
the sun, that radius of curvature is stable. Such a circular
orbit
is illustrated around the shaded area on figure 1. In that case, the
moving
mass is always at the same constant distance ro from the sun.
Figure 1
Consequently,
in a circular orbit, the mass is continuously subjected to a constant
gravitational
force, which is always exactly compensated by an equal constant
centrifugal
force everywhere on the orbit. The centrifugal force F(centri) and the
gravitational force F(grav) are exactly equal and opposite, so that
their
sum is everywhere zero at the distance ro from the sun. We
have:
 |
1 |
In this
paper,
only a single plane of the orbits needs to be considered.
Let us
consider
that at the distance ro from the sun, the curved trajectory
represents a curved axis of coordinates (the curved horizontal axis on
figure 2) along the circular trajectory around the sun. Planet Mercury
travels at a constant velocity V along that curved axis. At radii r+Dr
and r-Dr, (dashed circles on figure 1), the
corresponding (dashed) parallel lines to the ro axis are
drawn
on figure 2. Of course, there exists no force F accelerating the
mass along this tangential direction, since the centrifugal force
compensates
for the gravitational force at ro. This axis is
perpendicular
to a radial r-axis (drawn vertically on figure 2).

Figure 2
Since we
have
seen in equation 1 that the two forces cancel out at a distance ro,
there
remains
no net force Fr, in the radial direction, as
long
as the distance of the mass from the sun remains ro.
If, at one
point on the orbit, the mass is deflected toward an outer direction
(illustrated
at "m" on figure 1), its distance r from the sun increases. However,
its
velocity will then gradually decrease because of its increasing
gravitational
potential in the new direction further away from the Sun. Therefore,
the
slower particle will gradually have a "radius of curvature" (around the
aphelion in A, on figure 1) smaller than its distance (radius r+DR)
from the Sun. This will then make the mass fall back to a closer
distance
to the Sun. Then, when approaching the perihelion B, inside the initial
orbit ro, the velocity will then
increase
so that the radius of curvature will now be larger than its distance
from
the Sun. This phenomenon is repeated periodically at every rotation
around
the sun.
This
qualitative
description shows that in such an elliptical motion, the mass
oscillates
(along the radial r-axis) from one side to the other of the average
radius
ro, as shown in dotted (not dashed)
line
on figure 1. Since the mass oscillates on each side of the average
radius
ro, there must exists a net force,
always
pulling it in the opposite direction, always toward ro.
Let us calculate this force.
3 -
Constant
Curvature of an Ellipse with a Small Eccentricity.
We can see
in Appendix I, a geometrical
demonstration showing
that an ellipse with a small eccentricity (first order) is identical to
a circle in which the center has been shifted. Therefore such an
ellipse
is a circle with a displaced center (first order). Let us demonstrate
now,
that the laws of physics also lead to a constant radius of curvature R
when a mass travels on an elliptical orbit (with a small eccentricity).
This means that the forces acting on the mass orbiting on an ellipse,
and
the velocity must be compatible with the constant (radius of) curvature
R of the ellipse.
Let us
define
the "radius of curvature" at one point on the ellipse equal to R, while
the distance from the sun is r. Therefore, R is the distance from a
point
on the ellipse to the center of the ellipse (point "C" on figure
7).
Since an ellipse with a small eccentricity is a circle with a radius R,
the centrifugal force must always lead to a constant radius of
curvature
R. We have:
 |
2 |
The radius
of
curvature R must remain constant even when the distance r from the sun
increases by ¶r. Equation 2 gives:
 |
3 |
Since we
have
an ellipse, the distance r from the Sun is a variable so that the
gravitational
force F changes. Furthermore, the velocity V on the orbit changes at
the
same time. Let us calculate an assumed variation of the radius of
curvature
R (if any) as a function of the gravitational force F and the velocity
V of the orbiting mass. The derivative of equation 3 is:
 |
4 |
This is
equivalent
to:
 |
5 |
The
gravitational
force F is equal to:
 |
6 |
Its
derivative
is:
 |
7 |
From
equations
6 and 7 we find:
 |
8 |
Let us
substitute
8 in 5, we find:
 |
9 |
Since the
velocity
of the orbiting mass changes when changing its distance from the Sun,
let
us apply the principle of energy conservation. When r is changing, the
variation of potential energy is equal (minus) to the variation of
kinetic
energy. We have:
 |
10 |
This gives:
 |
11 |
or
 |
12 |
It is well
known
in classical mechanics, that in a orbital motion around a central
field,
the kinetic energy of an orbiting mass is always (minus) half of the
potential
energy. Since this is well known, this will not be repeated
here.
This can be written:
 |
13 |
This gives:
 |
14 |
Substituting
14
in 12 gives:
 |
15 |
Equation 15
in
9 gives:
 |
16 |
Equation 16
can
also be written:
which is  |
17 |
Equation 17
shows
that a change
dr of distance r from the Sun
(in the neighborhood of ro), does not change the radius of
curvature
R on any point on the elliptical orbit. Since in equation 17 dR
equals
zero, this means that in equation 5, the relative change of velocity
dV/V
just cancels out the effect due to the change of gravitational force dF/F.
Therefore the elliptical orbit maintains everywhere the constant
curvature
R, even if the distance from the Sun is variable. This agrees with a
circle
with a displaced center as illustrated on figure 1 (also in Appendix
I).
4
- Spring Constant
On figure
1 and 2, we see a larger circular orbit at (ro+Dr)
and a smaller circular orbit at (ro-Dr)
illustrated
by
dashed lines, while the elliptical orbit of Mercury is
illustrated
on figure 1 using a dotted line. We can see (especially on figure 2),
that
those circular trajectories at ro+Dr
(and
ro-Dr) are parallel to ro
(at
A and B). When the mass is located in A, we see (figure 1) that
the
elliptical orbit does not remain at a constant distance from the
original
circular orbit (solid line). In order to remain at a constant distance,
the particle (on the elliptical orbit) would have to continue along the
dashed circular orbit having a radius ro+Dr.
Therefore,
with
respect to this circular orbit, there is a force on the
elliptical orbit, bringing the mass back toward the radius ro,
when
the
particle is A.
Similarly,
when the elliptical orbit passes at the perihelion, at point B, inside
the initial orbit ro, there must be a force pushing the mass
back externally, toward the initial radius ro. That force
(pushing
the mass back toward ro), that exists for the elliptical
orbit
does not appear for the circular orbit at ro-Dr.
Let us calculate that force (always pushing the particle back to the
radius
ro).
It is clear
that the force pushing the particle back to the radius ro at
a distance ro±Dr, is equal
to the difference of force between the circular orbit and the
elliptical
orbit passing by A or B. Both the elliptical and the circular orbits
pass
through a common point at A, (where of course the gravitational force
is
the same). Keeping everything else (i.e. energy, velocity and
potential)
constant, let us calculate the change of force necessary at A, so that
the radius of curvature of the mass in the elliptical orbit become
equal
to the radius of curvature of the circular orbit. This is the force we
are looking for in order to make the two orbits parallel in A. It is
that
difference of force that brings the mass from the distance ro+Dr
back to ro (after a quarter of rotation).
In the case
of the circular orbit having a constant radius ro, the
gravitational
force is equal to the centrifugal force so that the sum of the forces
is
zero. We have:
 |
18 |
From
equation
18, for the circular orbit ro, we have:
 |
19 |
The reason
for
which the mass traveling on the ellipse at location A (figure 1), moves
back to the orbit (toward the average radius ro) is because
its velocity had decreased previously, when the distance increased from
ro to ro+Dr.
This
is a consequence of conversion of the total kinetic energy into
gravitational
energy. When the ellipse passes at location A, the distance from
the Sun is ro+Dr.
Let us
calculate
the change of force on the orbiting mass, as a function of the distance
from the Sun. There are two variables, v and r. The
derivative
of equation 18 gives the change of force as a function of the radius r
and the velocity v. We get:
 |
20 |
At location
A,
the gravitational potential has increased. Therefore the velocity
v must decrease. Knowing that the total energy is conserved, let
us calculate the change of velocity as a function of the distance r
from
the Sun. The relationship between the kinetic energy and the
potential
energy is:
 |
21 |
Let us
calculate
the derivative of equation 21. The substitution of equation 21 in
its derivative, gives the relationship between the change of velocity
with
respect to a change of radius when energy is conserved. Equation
21 and its derivative give:
 |
22 |
Therefore,
the
change of force calculated in equation 20 can now be expressed as a
function
of one unique variable dr. Equation
22
in 20, and then substituting equation 19, we get:
 |
23 |
Equation
23 gives the change of forces bringing the mass back toward ro.
This
is
exactly the force involved in the elliptical orbit passing
through
location A. This extra force would transform the large circular orbit
in
A into the elliptical orbit as illustrated on figure 2. Similarly, we
find
that the same extra force must be applied in the opposite radial
direction
at location B to bring the particle back to the initial external radius
ro (also illustrated on figure 2 and at location B on figure
1). Then in that case, Dro is
negative.
Consequently, this shows mathematically, that the mechanism of
translation
of a mass around the Sun is such, that for an ellipse, with respect to
the corresponding circle, there is a force bringing the mass back to
the
initial ro every time a mass is deflected from its initial
orbit.
Whether the mass moving on the elliptical path is "inside" or "outside"
the circle, the force always push the mass back toward the circle ro.
Furthermore,
this
force is proportional to the distance
dr,
as calculated above (equation 23). We must notice that this force has
the
same mathematical form as the force of elasticity known as Hooke's law.
This force is responsible for the elliptical shape of planetary orbits.
5 - Harmonic Oscillator.
What is the
behavior of a mass submitted to such a force, which always brings back
the mass toward the opposite side of the average radius? According to
equation
23, that force focuses toward ro, all orbiting masses, with
a force which is proportional to the width of the shaded area
illustrated
on figure 2. In classical mechanics, that force is characterized by the
constant k, (called the spring constant). It is a force per unit of
displacement
(along the r-axis). The force of a harmonic oscillator [2]
is defined by the relationship:
 |
24 |
In classical
mechanics,
we know that in order to produce a periodic oscillation across ro,
the
value
of k must be positive, just as obtained above. This problem,
well known in physics, has been solved centuries ago and is recalled in
numerous textbooks [2]. We know that a force is
the
second derivative with respect to the distance r. We have:
 |
25 |
Equations
24 and 25 give:
 |
26 |
The solution
of
equation 26 is a sine wave, oscillating on each side of the central
position
ro. The period of oscillation P(osc) is:
 |
27 |
Substituting
the spring constant k existing on our elliptical orbit as given above,
equation 23 into 27 gives:
 |
28 |
Equation
28 gives the period of oscillation P(osc) of the mass on each side of
the
radius ro along a curve axis. It is very important to notice
that equation 28 has been obtained independently of the time taken by
the
mass to complete a revolution of 360 degrees around the Sun. Equation
28
gives the period to complete one full oscillation across
either side of the average radius ro. That period of
oscillation
depends on the spring constant k. It is completely independent of the
velocity
of the mass along the orbit and of an assumed length of a trajectory.
However,
the period of rotation (2p
radians)
of Mercury around the Sun at the distance ro, depends on the
circumference of that orbit and the velocity of the mass on that
trajectory.
It is completely independent of the period found above using the spring
constant k.
6 - Comparing two Independent Periods; P(osc) and
P(rot).
Let us now
compare the time P(osc) taken by the mass to complete one full
oscillation
on either side of the average radius ro of a circla, and the
time P(rot) taken by the same mass to complete one full rotation around
the Sun. In the calculation of P(osc), we use the relationship
(equation
28), giving the period of oscillation of the particle across the radius
ro. Let us transform the parameters under the square root
(in
equation 28) as a function of the velocity V of the mass moving around
the Sun. We know that the gravitational force Fg around the
Sun is equal to the centrifugal force Fc. We have:
 |
29 |
where rs is the radius of the orbiting
distance
of the mass from the Sun.
Equation
(29)
gives
 |
30 |
Equation
30 in 28 gives:
 |
31 |
Equation
31 is the period of oscillation P(osc) of the mass on either sides of
the
average radius ro. However, the period of rotation P(rot) of
Mercury around the Sun can then be calculated independently, using a
simple
geometrical relationship. From the relationship using the perimeter of
the trajectory divided by the velocity, we get:
 |
32 |
Equation
32 uses the circumference of a circle equal to the perimeter of an
ellipse
having a small eccentricity. This is demonstrated in appendix
I of this paper. Consequently, when we do not apply any correction
for mass-energy conservation, as done usually with Newton's equations,
we find that equations 31 and 32 show an extraordinary coincidence
between
the period of oscillation P(osc) of a mass across the average radius ro
and the period of rotation P(rot) of the same mass around the Sun. We
have:
 |
33 |
Let us
notice
that such a coincidence would not exist if the gravitational field
around
the Sun would not decrease exactly as an inverse quadratic function.
This
has been shown in more detail previously [1]. A
difference
would appear in equations 23 and this would not lead to an equal phase
relationship between the periods of oscillation and rotation. This is
well
known mathematically. Since these two independent periods P(osc) and
P(rot)
are identical for the inverse quadratic force existing around the Sun,
the period of rotation around the Sun coincides with the period of
oscillation
of the body across the average radius ro as required by
Kepler's
laws and observed experimentally. Therefore, the major and minor axes
of
the ellipse are always pointing in a constant direction in space as a
function
of time. The equality of the period between the oscillation on both
sides
of the radius and the rotation around the Sun is illustrated on figure
3. Both periods P(osc) and P(rot) are the same.

Figure 3
The result
above
has been obtained using the conservation of potential plus kinetic
energy
but
without mass-energy-conservation.
When energy (kinetic or potential) is given to a mass,
the mass of that energy is given to the mass having received that
energy,
following the relationship E=mc2 as demonstrated
previously. Let us now take into account the principle of
mass-energy
conservation.
7 - Fundamental Considerations.
In physics,
a natural description of the period of rotation is given as the time
taken
by a body to complete one full rotation by 360 degrees or 2p
radians around the Sun. We will see now that Newton's laws do not lead
to a perfect ellipse (without precession) when the principle of
mass-energy
conservation is strictly applied. The fundamental reasons have been
explained
in the book entitled Einstein's Theory of Relativity versus Classical
Mechanics
[1]. The full explanations and calculations are too long to be repeated
here. You find them explained in detail in the book
[1]
but they are also available on the internet. Only a concise description
of the fundamental principles is recalled here using some examples. The
study of the original paper [1] is
indispensable
for the complete understanding of the phenomenon.
Let us
mention
first that the principle of mass-energy conservation is one of the most
important fundamental principles in physics. This principle is always
valid
and must never be neglected and transgressed. This principle implies
that
we cannot create from nothing and we cannot annihilate into nothing.
Mass
and energy are two different aspects of the same constituent of matter.
Energy (E) always possesses mass (M) and mass always possesses energy.
Mass can be transformed into energy and vice versa. The ratio of
proportionality
between mass and energy is a constant, which happens to be equal to the
square of the velocity of light.
Serious
consderations
in physics shows that when kinetic or gravitational energy is given to
a frame of reference, that increase of energy increases the mass of the
frame, corresponding to the amount of energy given to the frame,
according
to E=mc2. Whatever the system
of
reference used in the energetic frame to determne the standard
references,
we have seen that the local reference standards of mass, length and
clock
rate change during the passage from rest to the energetic frame.
However, that change of local reference standards are undetectable
locally
in the moving frame, because matter forming the frame is submitted to
the
same increase of energy as any other matter used to do experiments
inside
the moving frame. Therefore, after the acceleration of both, a
frame
and all local matter used to do a local experiment, have increased
their
energy, and therefore their mass. Therefore, locally inside the
frame,
this is undetectable. This is required by the principle of
mass-energy
conservation "between frames".
The
calculation
of the Bohr atom, involving quantum mechanics is also requires in that
claculation, as demonstrated previously in the book: Einstein's Theory
of Relativity versus Quantum Mechanics. For example, let us
consider
a grain of sand in space moving around the Sun at the Mercury distance,
having a mass of one million atoms. When this grain of sand is moved
from
Mercury orbit around the Sun to the Earth's distance from the Sun (or
about
an infinite distance), we need extra energy to move it against the
gravitational
potential of the Sun. The extra energy can be obtained at the cost of
transforming
some mass into energy. Suppose that, to provide the required energy to
raise the grain of sand from Mercury orbit, to Earth's distance from
the
Sun, it is necessary to transform one atom of mass "m" into energy (E=mc2).
We also assume that that extra energy (extra atom) is taken from an
external
source near Mercury's orbit. Therefore the total number of atoms
leaving
Mercury's orbit around the Sun is 1 000 000 (plus the equivalent energy
of another one). Then, while the grain of sand is moved away from the
Sun,
the energy of the disintegrated atom is used up gradually (like
"dissolved"
into the mass of the grain of sand), so that finally, the number of
atoms
reaching the Earth distance is again one million, after having
transformed
the energy of the atom into gravitational (potential) energy.
Then the
total
number of atoms is the same at Mercury orbit from the Sun (which is
1000000
Mercury atoms plus energy) as at Earth orbit from the Sun (which is
agan
1 000000 Earth atoms). Therefore 1000001
atoms
at Mercury orbit has the same total mass-energy as one million
atoms
at Earth orbit. The mass-energy produced from the disintegration of one
atom has been given to all other atoms. The logical explanation implies
that each atom has an extra mass-energy after reaching the Earth
orbit.
They have a slightly larger mass than the atoms at a lower potential
energy
on Mercury orbit. There is no other way to satisfy the principle
of mass-energy conservation.
One can see
that the same relative change of mass-energy must also exist on the
standard
reference kilogram used on Earth's orbit from the Sun. The standard
reference
kilogram can be defined by an absolute number of atoms. The standard
kilogram
simply contains a much larger number of atoms than a grain of sand. The
principle of mass-energy conservation requires that one
Mercury-kilogram
(at Mercury distance from the Sun) contains slightly less mass-energy
than
the Earth-kilogram (at Earth distance from the Sun), even if the number
of atoms is exactly the same. That change of mass of each atom is real.
It is not an illusion. This is required by the principle of mass-energy
conservation.
There are
several other logical consequences to that change of mass of bodies,
due
to gravitational or kinetic energies. Since the real physical mass of
bodies
changes when we add energy, one must realize that particles, like
electrons
and protons of atoms, forming those masses must logically also change
their
mass, exactly in the same proportion as atoms. Furthermore, using
quantum mechanics [1], one can show that a
change of
electron and proton mass modifies the length of the Bohr radius. Due to
that change of the Bohr radius, the physical lengths of bodies and the
energy of the quantum levels change when gravitational or kinetic
energy
is added to a mass. All these phenomena have been explained and
calculated
previously [1].
Following
the change of the Bohr radius, quantum mechanics also predicts a change
of quantum levels, due to the change of electron mass, implying also a
corresponding change of rate of atomic clocks [1]
.
It is also required that all matter, including organic matter and even
human bodies, function at a different rate when electrons forming them
have acquired or released some potential or kinetic energies.
Since
Mercury in its orbit has a different gravitational energy and possesses
a different kinetic energy, matter on Mercury (i.e. due to its Mercury
distance from the Sun) has a different mass. In addition, clocks on
Mercury
are functioning at a different rate due to the change of electron mass.
However, we
have seen above that that change of mass, length and clock rate is
undetectable,
because matter from this frame, that forms the standards of
reference
in a frame, changes in the same proportion as the local matter being
investigated
inside the same frame. Consequenlty, the experimental parameters
(number of units) measured in the energetic frame are identical to the
ones in the initial frame, but they are not coherent with the increase
of mass-energy between the two systems of reference. Since
the increase of mass-energy in the energetic frame is real, the
numerical
values measured inside the energetic frame are not compatible with the
principle of mass-energy conservation and therefore are in error.
The relative size of the standard references must be calculated.
The relationships transforming the standard units between locations at
different gravitational potentials and different velocities have
already
been calculated
[1] . The length of the radius
of the orbit of Mercury is a number which is equal to the number of
Mercury-meters
times the length of the local standard Mercury-meter. However, that
number
is not equal to the number of Earth-meters to measure
the
same orbit of Mercury, because it is measured using the shorter
Earth-meter.
We must notice that Newton's laws of physics deals with the numbers
that are fed into the equations. Since the number of
meters
to measure the "same physical length" (using the longer
Mercury
meters) is smaller than the number of Earth meters, we
must
take that difference into account.
In physics,
there exist several systems of units using meters, feet, kilograms,
pounds,
coulombs, statcoulombs, abcoulombs etc. that have been devised in a
coherent
way so that the coherent use of any set of reference units leads to
answers
which are compatible, independently of any system of units. In fact,
one
has a complete choice of systems of reference units that leads to the
same
"physical" answer, although represented by different
numbers
when using units having different names. However, contrarily to the
above,
when we apply the principle of mass-energy conservation between frames,
the units of mass, energy, lengths and clock rates in different frames
cannot be the same. Most importantly, the principle of
mass-energy
conservation must be satisfied. The correct calculation requires
coherence between frame. Therefore the local number of units must
be corrected with respect to the Earth value considered at infinity. We
show here below, that this logical correction explains perfectly the
advance
of the perihelion of Mercury without any relativity principle.
In the
calculation
below, for simplicity, we make the approximation that the Earth is
infinitely
remote from the Sun. Therefore we consider that the Earth is
located
in Outer Space. The number of meters of the Earth from the Sun is
noted "NO.S.
".
Corrections due to the residual Earth gravitational potential can be
easily
done later. Furthermore, when we say that a mass is near Mercury, one
must
understand that it at a location near the Mercury orbit, assuming that
the gravitational energy due to Mercury is zero.
As explained
previously [1], since the number of local units
corresponding
to local standards of length, mass and clock rates are numerically
different
in different frames, (due to mass-energy conservation) these different
reference standards must be clearly identified without ambiguity. A
special
notation must identify clearly in what frame the unit is calculated.
Our
notation uses a sub index to refer to the proper units in use. Notation
[meterM] represents the "physical"
length of the standard Mercury meter, and [meterE]
is the "physical" length of the Earth meter. Therefore
these
"physical"
lenghts
are local "etalons". Also, [N-LengthM],
is the number of Mercury meters corresponding to the physical length [LM],
and [N-LengthE] is the number of
Earth
meters corresponding to the physical length [LE].
For example, the physical length (in Earth meters) of the radius of the
orbit of Earth is:
 |
34 |
Using
Mercury
meters, the same absolute physical length (distance) is given by:
 |
35 |
Of
course,
when we measure the same "realistic physical quantity", we have:
 |
36 |
In the
above
description, there is no non-realistic concept like "space
contraction".
There is just a real physical change of length of matter due to the
change
of the Bohr radius, required by the principle of mass-energy
conservation.
Equations
34
and 35 can be used to measure any object located
on
Earth, on Mercury or anywhere else having a different kinetic energy or
gravitational potential. Applying mass-energy conservation, we have
explained
previously (Chapter 5, equation 5.31 of [1])¸
that the relationship between the Bohr radius of the atoms of the
Mercury-meter
[meterM,v,]
having
a
velocity v, and the atoms of the "Outer Space" meter [meterO.S.,
0,
] with velocity zero, can give the relative
lengths
between the two standard meters, one on Mercury with respect to another
one in Outer Space. Since we are able to determine the increase
of
Bohr radius as a function of Gravitational and Kinetic Energy, we are
able
to establish the relative "number" of local meters between frames
leading
to the same real physicsl length.
We
have
seen in the book: "Einstein's Theory of Relativity versus
Classical
Mechanics" in Chapter 5, equation 5.31, that the relative length of the
standard reference meter between a meter (meterO.S.
) in outer space and another one located in a gravitational potential
at
the Mercury distance (meterM)
from the Sun. That relationship 5.31 in chapter 5 is:
 |
37 |
We
have,
[NO.S., 0] is the "Number"
of
meters in Outer Space (when velocity is zero). Also [NM,V,]
is the number of meters on Mercury when the velocity is V.
Equation
37 gives the relative number of meters in each frame so that the the
same
real length is represented in both frames. We recall that
equation
37 takes into account both, the increase of potential energy due to the
gravitational energy, and also the change of kinetic energy (velocity)
when a mass passes from the Mercury orbit to a higher orbit. In
equation
37, the coefficient 3/2 to (Gm'/c2RM)
is the sum of the two phenomena explained in Ref, [1] Chapter 5.
We have shown that there is a component (Gm'/c2RM),
which is the contribution due to the increase of potential energy,
while
the component (1/2)(Gm'/c2RM)
is the contribution due to the slowing down of the velocity of the
frame
in a higher orbit.
Therefore,
the
change in the number of units in equation, 37
corresponds
to the change of the number of units of length taking into account the
change of gravitational potential as well as the change of velocity of
an orbiting mass at different distances around the sun. Here, for
simplicity,
we can substitute the location of Earth with "Outer Space", if we
accept
the approximation that the Earth is sufficient close to outer space
with
respect to Mercury. However, in order to obtain the exact change
of number of meters between the Earth orbit and the Mercury orbit, a
remaining
small correction can be done with respect to outer space, if we
wish.
Taking into account that we compare the "number" [N-rE]
of meters in a frame in the Earth orbit located at a distance rE
from the sun, with respect to the "number" [N-rM]
of meters in the frame located on the Mercury orbit at a distance rM
from the Sun, equation 37 becomes:
 |
38 |
We
have
e
is equal to:
 |
39 |
We have [N-rE]
and [N-rM]
representing respectively the number of Earth and Mercury meters to
measure
the same absolute length. We have m' is the mass of the Sun, G is
the Cavendish gravitational constant, c is the speed of light, and ro
is the distance from the Sun. As a practical example for Mercury orbit,
e
is about 0.000 000 025, therefore e2
is always neglected in all calculations, in equations and in all series
expansions in this paper. As given by equation 38, the observer on
Earth,
measuring the same Mercury orbit but using the longer Mercury meter,
will
feel that the distance from the Sun is smaller, because the number of
local
meters [N-rM]
needed to measure the same absolute physical length is smaller.
8 - New Orbiting Velocity.
Classical
mechanics predicts that the orbiting velocity of a planet is larger
when
the number of meters measured from the Sun to the planet is smaller.
This
is well known as Kepler's laws. Using classical physics, we have seen
that
the kinetic energy of an orbiting planet around the Sun is (minus) half
the gravitational potential (see equation 13). We have:
 |
40 |
The
potential
energy is:
 |
41 |
The
kinetic
energy is:
 |
42 |
Therefore,
from equations 40, 41 and 42 we have:
 |
43 |
This
gives:
 |
44 |
Let us
consider
that we displace the orbiting mass by a small radial distance
dr.
Using the derivative of equation 44, we find that the required
corresponding
physical change of orbiting velocity dV
with
respect to the change of radius dr is:
 |
45 |
Substituting
44 in 45 gives:
or |
46 |
From
equation
46, we see that when the number of radial units r decreases (due to
energy
conservation), Newton's laws require that the relative (number of units
of) velocity increases by (minus) half the relative change of radius.
Using
the principle of mass-energy conservation, we have seen above in
equation
38
that
the number of Mercury-meters [N-mM]
is
different from the number of Earth-meters [N-rE]
(when measuring the same absolute length). When
an
observer on Mercury measures the length of his orbit around the Sun, he
will measure it using his longer Mercury meter. Therefore he will
find a smaller "number" of meters, than if measured by the Earth
observer
(who uses the Earth meter). From equation 38, we find that that
smaller
number of local meters on Mercury is given by the relationship:
| [N-rm]
=(1-1.5e)[N-rE] |
47 |
This
variation
of the number of meters can also be expressed as a
fraction
representing the relative change of number of meters (between the
Mercury
measurement and the Earth measurement) with respect to the total
number.
Using equation 47, we have:
 |
48 |
The
Mercury
observer also wishes to measure the change of velocity of
his
planet using his own units, and compare it with a measurement done by a
remote Earth observer. We have seen in equation 46 that the
relative change of velocity is minus half the change of radius.
Using
that relationship, let us calculate the relative change of
velocity.
Putting 48 in 46 gives:
 |
49 |
Let us
express
that function as the "number" of meters. The relative change of
number
of Earth-units of velocity with respect to the number of Mercury-units
of velocity, from equation 49 gives:
 |
50 |
Equation
50 can also be written:
 |
51 |
Let us
discuss
the physical phenomenon implied in equation 51.
We
know that "locally", Newton's laws of physics are always valid in all
frames.
For example, if the Earth orbit would drift near the Sun at the Mercury
distance, we would still be submitted to exactly the same Newton's
equations,
using
the local units of length and time etc. . .. existing on
Mercury. Newton equations are always perfectly valid locally
inside
all frames, on the condition that we use local units.
Therefore
the
solution presented in this paper will be compatible with
that fact. However, using his local standard units of reference,
and newton's laws, his calculation will not be compatible with the fact
that there is an advance of the perihelion of the elliptical
orbit.
For the Mercury observer, the perihelion of the orbit is not
local.
The observer of Mercury must modify the data obtained in his own
observation
in order to be compatible with the fact that the line passing through
the
Sun and his own planet is speeping the sky as a function of time.
Therefore the Mercury observer must use the correct (Outer Space)
standard
units of reference, which are not the standard units existing locally
on
his frame.
Let us us
now consider the length of the corresponding circular orbit.
Since
Mercury travels at a higher velocity than previously calculated with
Earth
units, the time taken by Mercury (period of rotation) around the Sun is
reduced. We see in equation 51, that this period of rotation, giving
the
time taken to complete a rotation of 360 degrees or 2p
radians around the Sun is shortened. However, in compatibility with the
principle of physical reality, there is a difference between the real
length of the trajectory to complete this circumference for an observer
using Mercury units and for an observer using Earth units.
We will see
here that the advance of the perihelion of Mercury is due to the fact
that
Mercury actually travels a longer path, (longer than 2pr)
before the elliptical orbit is closed (because we have applied Newton's
laws combined with Mercury units). We see below that due to the
larger
velocity required by Newton's laws, using Mercury units, it takes a
shorter
time to complete 360 degrees on the circumference of Mercury
orbit.
We have shown above in sections 2, 3, 4 and 5, that an ellipse
corresponds
to an oscillation on each side of the curved axis of a circle.
Using
Earth units in both frames, (which is wrong) when calculating the
period
of oscillation on each sides of the ellipse in equation 31, we found in
equation 33, that it takes the same time to complete the oscillation on
either sides of the circle than the time to complete the rotation of
360
around the Sun. However, using the number of Mercury units,
corresponding
to the same physical length, we will see below that it takes a
different
time to complete the oscillation on either sides of the circle
(equation
31) than the time to complete the rotation of 360 around the Sun.
9 - Taking into Account Mass-Energy Conservation.
Let us apply
equation 28 to the classical units existing on Earth. We have seen that
the period of oscillation of Mercury on both sides of the average
radius
ro calculated by an observer on Earth would be calculated as:
 |
52 |
In
equation
52, the physical quantities have been substitued by the corresponding
"number"
of units. However, this equation cannot be applied without
corrections,
because this equation uses masses (and all other units) as they exist
on
Earth, while the interacting mass with the solar gravitational field is
different at Mercury orbit (as mentioned above). We recall that the sub
index E (as in PE) means that the
units
used are the ones existing far from the Sun where the principle of
mass-energy
conservation does not require correction. From equation 37, we
can
see that on Earth, the standard meter is shorter than on Mercury.
Therefore,
the number of Earth-meters [N-rE] is
larger
than the number of Mercury-meters [N-rM],
when
measuring
the same physical length. We have:
 |
53 |
In equation 39,
we have:
 |
54 |
We know that
G
is an absolute physical constant. However, since the standard units
existing
on Mercury are different from the standard units on Earth, different
numbers
will then express the same physical gravitational constant G. The
gravitational force at one point is physically the same, independently
of the units used by the observer. However, the number of units
to
describe it will be different, since the reference units are different,
but this will represent the same field and the same physical
force.
Therefore we have to calculate the relationship giving the change of
the
number of local units of the gravitational constant G due to the change
of standard units on Mercury in compatibility with the principle of
mass-energy
conservation. The change of the number of units [N-G] of G has been
calculated
previously ([1] Chapter
4 Equation 4.65) in the case of zero velocity. We
must then compare the numerical value of G when two conditions are
changed
simultaneously. One is due to the physical change of velocity as given
in equation 51. The other is a mathematical transformation, because we
have to express the very same physical quantity using different
standard
units (from Earth units to Mercury units).
Let us
calculate
the relationship between the number of gravitational units [N-GM],
and [N-GE], resulting from those two
changes.
This can be done using the relationship giving an equal force between
the
gravitational force and the centrifugal force. Since the centrifugal
force
must always be equal to the gravitational force using proper values, we
have in all frames, (when using proper units):
 |
55 |
This
is
mathematically equivalent to:
 |
56 |
Let us
use
the correct notation showing the number of units. To get
the correct physical answer, one must use the number of
Mercury-units,
since it is the relevant number of units existing at the location where
the phenomenon takes place. The change of the number of units of
G can be calculated using the relationship 56 equals to G. Using
the notation, and taking into account the number of units leading to
the
same quantity, equation 56 should be written:
 |
57 |
Let us
compare
this number [N-GM] in Mercury units,
with
the number [N-GE] of units of G on
Earth.
On Earth, the relevant number of units is:
 |
58 |
Due to
the
physical change of velocity given by equation 51, we have seen that:
 |
59 |
From
equation
37 when we measure the same physical length, we find that the change
from
the number of Earth-meters [N-rE] to
the
number of Mercury-meters due only to mass-energy conservation gives:
 |
60 |
Since
we
are using Mercury units, let us now calculate the solar mass. We want
to
determine the number of Mercury kilograms required to be
equal to the mass of the Sun. However, the Mercury kilogram has to be
given
as a function of the Earth kilogram, which is assumed at rest and
sufficiently
far from the gravitational potential of the Sun. Therefore, the number
of units of Mercury-kilograms will be different from the standard Earth
kilogram, because the Mercury kilogram is located deeper in the
gravitational
potential of the Sun and furthermore because of its velocity.
The change
of the number of Mercury kilogram [N-mM]
, to measure the solar mass, instead of the Earth kilogram, is
calculated
in the following way. Due to the gravitational energy, the Mercury
kilogram
(at rest) is smaller than the Earth kilogram (at rest). Due only to
gravity,
equation: (see [1] chapter 4
equation
4.42)gives:
(Due only to gravity) |
61 |
Where
the
indexes (E) and (M) give respectively the location of the mass on Earth
or on Mercury. Here those masses are expressed in Mercury units (using
the sub-index "M"). In addition, we know from Newton's laws, that the
kinetic
energy of an orbiting mass around the Sun is half the (negative)
gravitational
potential energy. Consequently, the kinetic energy of Mercury gives a
larger
mass on Mercury (expressed in Mercury units) than at rest (always on
Mercury):
 |
62 |
Combining
equations 61 and 62, we find that the relative mass of a
Mercury-kilogram
in motion [mM(m)(moving)] with
respect
to an Earth-kilogram at rest on Earth [mE(E)(rest)] is
(expressed
in Earth units):
 |
63 |
Therefore,
the moving standard Mercury kilogram is slightly less massive than the
standard Earth kilogram at rest when common units are used.
However,
the quantity required is different. It is the number of
Mercury
kilograms to equal the mass of the Sun. Of course, the absolute mass of
the Sun does not change because it is measured with respect to the
Mercury
moving kilogram. However, the number of Mercury
kilograms
that represents the Sun will be different. From equation 63, we can
deduce
that the number of Mercury-kilograms in the Sun is
larger
than the number using Earth-kilograms according to:
 |
64 |
We can now
calculate
the number of gravitational units [N-GM].
Putting
59,
60 and 64 in 57 gives:
 |
65 |
Always
neglecting
e2
and higher powers of e with respect to e
, equation 65 is equal to:
 |
66 |
Using
equations
66 and 58, we get:
 |
67 |
We
have
taken into account that the absolute physical value of the universal
gravitational
constant G never changes. However, since it is now measured using
Mercury
units, its numerical value has changed. Furthermore, we have seen that
the velocity (equations 51 and 59) of Mercury has changed. Equation 67
has taken these two phenomena into account.
Let us now
calculate the period of oscillation on each sides of the radius ro.
Substituting
60,
64, and 67 in 52, we get:
 |
68 |
 |
69 |
 |
70 |
The
period
of oscillation of Mercury calculated with Mercury units is then:
 |
71 |
Similarly
to equation 52, we can easily formulate the period for the Mercury
observer.
Combining equation 51 with 71 gives:
 |
72 |
Equation
72 gives the period of oscillation [N-PM(osc)]
of Mercury on either side of the average radius with respect to the
initial
period of oscillation [N-PE(osc)]
using
Earth parameters (from infinite distance). We have seen that [N-PE(osc)]
is the period when mass-energy conservation is not considered (or when
we are at a near infinite distance from the Sun and with near zero
velocity).
However, since the period of oscillation [N-PE(osc)]
without mass-energy corrections is identical to the (initial value of)
period of rotation (see equation 33), then equation 72 shows the
increase
of period with respect to a fixed direction in space.
10 - Relative Distance Reached after One Rotation
and
One Oscillation.
We have seen
in equation 51 that, in order to satisfy Newton's physics with the
local
parameters, Mercury must travel more rapidly on its orbit according to
the relationship:
 |
73 |
Even
if
Mercury travels more rapidly on its orbit, the length of the perimeter
of the orbit to complete 360 degrees or 2p
radians
does not change. Consequently, the length traveled by Mercury to turn
360
degrees around the Sun does not change even if the velocity is
increased.
However, we
have seen in equation 72 that due to the change from standard Earth
units
to standard Mercury units, Newton's equations give a longer period of
oscillation
of Mercury (longer time) on either side of the average radius ro.
Due
to
that longer period of oscillation, Mercury will travel a longer
distance before closing the ellipse. Furthermore, since the physical
velocity
V of Mercury is larger (due to mass-energy conservation) as seen in
equation
51, the distance traveled on the orbit becomes longer due to the increase
of
period,
but also due to the increase of velocity.
Let
us compare the distance traveled by Mercury to complete one full
rotation
by 360 degrees with the distance traveled to complete an oscillation,
which
closes an elliptical orbit. The distance traveled when completing one
oscillation
is:
 |
74 |
We
have
seen that due to the use of Mercury units and the local agreement with
Newton's laws (using proper values), the real physical velocity of
Mercury
is larger according to equations 51 (and 59). The corrected velocity
[N-V(corrected)]
with respect to the non-corrected velocity [N-V(non-corrected)] is:
 |
75 |
Similarly,
as demonstrated in equation 72, due to the change of standard units on
Mercury, the same physical forces measured with the Mercury units, lead
to a slower period of oscillation across the average radius ro.
This gives:
 |
76 |
The
correction
of length needed to close the elliptical orbit is given by the
parameters
corrected for mass-energy conservation. Equation 76, written correctly
becomes:
 |
77 |
Substituting
equations 75 and 76 in 77, we get:
 |
78 |
Taking
into
account that
e is extremely small, we neglect
the second order term (e2).
Equation 78 becomes:
 |
79 |
This
is
also equal to:
 |
80 |
Let us
note
that the relative change of distance of equation 80 (or relative change
of angle) is the same whether we use Mercury meters or Earth meters (we
neglect higher orders in e2).
The indexes E or m are useless since the increase of angle a
is the same in both frames, as expected logically. Equation 80 is
illustrated
on figure 4.

Figure 4
On figure 4,
the
circumference of the orbit is unrolled at the average radius ro
(circle) and forms the "Distance" axis. We have seen that the
circumference
of the orbit is not changed since Mercury orbits around the Sun is
calculated
at the same absolute radius ro. However, the real distance
traveled
by Mercury during one full transverse oscillation is longer than the
translation
of 360 degrees, due to the slower oscillation on each sides of the
radius
ro and the increase of velocity resulting from the use of
Mercury
parameters. This explains the advance of the perihelion of Mercury.
Let us
compare
equation 76 with Einstein's predictions and astronomical observations.
From equations 38 and 80 we get:
 |
81 |
Equation
81 shows that the advance of the perihelion of Mercury, calculated
above
with a small eccentricity is mathematically identical to
equation
5.45 in section 5.10 of [1]. Without the second order e2
for the eccentricity, in the case of Mercury, this leads to an accuracy
of 96%. Taking into account the second order e2
for the eccentricity, the non-linear change of gravitational energy
adds
a small correction, which is now taken into account. It has been
previously
demonstrated
[1] (section 5.10)
that
the expression (1-e2) must then
multiply
the denominator of equation 81, because the gravitational potential is
not linear between a small and a larger elliptical orbit (taking into
account
the second and higher order terms). This previously demonstrated
phenomenon
[1]
(section 5.10) is not repeated here, but it is easily applied to
equation
81.
The final
equation then gives the change of distance to close an elliptical
orbit,
with respect to a rotation of 2p radians.
Using
equation 81, expressed as a function of the angle of precession Df
per century, and a larger eccentricity e explained in section ([1]
(section 5.10). We find that this gives [1]
(equation 5.45):
 |
82 |
Equation
82 is mathematically identical to Einstein's equation. Therefore, this
shows that the advance of the perihelion of Mercury can be fully
predicted
using only classical mechanics, without any of Einstein's hypothesis
and
without space-time distortion. Neither new physics nor any mathematical
hypotheses have been used in the above demonstration. Everything is now
logical, realistic, and based on mass-energy conservation.
11 -Illustration of the Advance of the Perihelion
of
Mercury.
Figure 5
illustrates
"in perspective" the periodic rotation of Mercury around the Sun. It
shows
the precessing elliptical orbit of Mercury (dotted curve) oscillating
on
both sides of the circular orbit at ro (solid line), while
the
Sun moves uniformly to the right hand side of the figure. The use of
the
standard Mercury units reduces the number of units representing the
force
(spring constant) which always pulls Mercury back toward the average
radius
ro. Therefore, the period of oscillation is longer. Then,
the
oscillation is not completed (ellipse not closed) when Mercury has
already
completed a full rotation (360 degrees) around the Sun. We see that the
ellipse is crossing the circle upward (at ro) after more
than
one geometrical rotation of 2p radians. The
upward crossing between the elliptical orbit (dotted line) and the
circular
(solid line) line is repeated only after a supplementary rotation angle
a
(after each 2p radians).

Figure 5
Figure 5
shows
this cumulative advance a after
several
rotations. The cause of the advance of the perihelion of Mercury is now
perfectly explained. We see that this demonstration has been done using
Newton's physical laws instead of non-realistic mathematical models.
This
paper shows the beauty and the universality of Newton's laws in
Galilean
coordinates. Those laws are valid internally, everywhere inside all
frames
when we use proper values. We msut recall that the basic principle of
mass-energy
conservation has also been foreseen by Newton [3].
It has been
reported that Einstein said: Since the mathematicians have
invaded
the theory of relativity, I do not understand it anymore [4].
It is the author's wish that the realistic physical explanations
presented
in this paper will never be drowned into the mathematics.
12 - Acknowledgments.
The author
wishes
to acknowledge the helpful encouragement of Mr. Bruce Richardson.
Stimulating
questions were also appreciated from C. Couture, S. Talbert, I.
McCausland,
T. Phipps and T. Durt.
<><><><><><><><><><><><>
Appendix I
Description of an Ellipse with a Small Eccentricity.
On order to
get
a physical description of the transformations of a circle into an
ellipse
with a small eccentricity, we must examine the fundamental properties
of
ellipses. There is a general belief that a circle becomes an ellipse
simply
by flattening the circle. It is not realized that for a small
eccentricity,
an ellipse is much better described as a circle in which the center of
forces is shifted away from the center. The flattening of the circle
appears
only as a second order in a series expansion as demonstrated here. Let
us start with a fundamental property of ellipses. One of the
definitions
of an ellipse [5] given by Brink is:
An ellipse is defined as the locus of a point the
sum of whose distances from two fixed points (the foci) is a constant.
From this
property of an ellipse, gardeners and others often construct ellipses
by
driving pins at the foci and running a loop of string around both pins,
leaving a certain amount of slack. A marker P is then placed inside the
loop and moved around in such a way as to keep the string taut. Since
the
amount of slack is constant, the sum of the distances of the marker
from
the foci is constant, and the marker traces out an ellipse. Such a
construction
is compatible with the exact definition of an ellipse given by Brink [5].

Figure 6
Figure 6
shows
an ellipse with a large eccentricity. The distance "a" is the
semi-major
axis and b is the semi-minor axis. The eccentricity e is given by the
relationship:
 |
A-1 |
It has
also
been demonstrated that an elliptical orbit illustrated on figure 6,
corresponds
exactly to the orbit of a body for which the center of forces (here the
Sun at F1) occupies one of the foci.
This
elliptical shape is the one followed by most comets. Let us examine the
way an orbit is gradually transformed from a circle to an ellipse.
First,
when the eccentricity increases, and before the circular shape of
theorbit
gets noticeably flatter, the center of forces (focus F1
where the Sun is located) drifts from the center of the original circle
C to the left focus at F1. For a
large
eccentricity, the minor axis 2b then starts to decrease with respect to
the major axis 2a, as the square of the displacement of F1.
Figure 6 above illustrates a large eccentricity. In the case of a small
eccentricity, this is studied using figure 7.
Figure 7
also
illustrates the locus of a moving point P for which the sum of the
distances
from the two foci (F1 and F2)
is constant. When the distance between the two foci is zero, we have a
circle and the two foci are superimposed at the same central location.
The radius of that circle is R. Let us move foci F1
to the left-hand side by the amount Dx
(from
C
to F1). We see on figure 7,
that
when the length of the string is kept constant, (equal to two R) the
sum
of the distances F1-S1-F2
does not change when Dx increases. The
focus
F2 moves always in the opposite
direction
and by the same amount as F1.
We also find
the same constant total distance F1-S3-F2
on the left-hand side when the point moving on the ellipse is at S3.
In that case, the major axis (in the horizontal direction) of the
ellipse
is constant (equals 2a) for any eccentricity, when the foci are shifted
more apart.

Figure 7
Let us
now
calculate the length of the (vertical) minor axis (2b) as a function of
the shift (Dx) of the focus F1.
The length of the string passing through F1-S2-F2
is equal to the length F1-S1-F2
(which is equal to the major axis). Consequently, using the triangle F1-S2-F2,
formed by the string, the semi major-axis "a" is constant while the
semi-minor
axis "b", (the distance S2-C), is
equal
to:
 |
A-2 |
Using
a
series expansion for ArcSin and Cos, equation A-2 gives:
 |
A-3 |
In
that
series expansion, there exists no term with power one of Dx/a.
Since Dx/a is infinitesimal in the
problem
studied in this paper, the correction for the change of "b" as a
function
of Dx (which is a quadratic function
(second order)) is insignificant. The flattening of the trajectory is
observable
only for a large value of Dx/a. This
shows that for a small displacement Dx
of
the
focus F1 with respect to the
center
of the orbit, the minor axis does not change appreciably with respect
to
the major axis and the original orbit remains practically circular,
even
when the center of forces has moved considerably apart (by Dx),
as seen on figure 7.
Let us
consider
a numerical example. An elliptical orbit, at an average distance of
about
50 million of kilometers from the Sun, and having an amplitude of
oscillation
of one kilometer with respect to the exact circular orbit, implies that
the Sun is one kilometer away (value of Dx)
from
the
central circle. From equation A-3, (and other calculations) we
can also show that in that case, the major axis has not changed at all
and that the change of perimeter of this elliptical orbit, with respect
to the circular orbit is surprisingly small. For such an astronomical
orbit,
for Dx equals one kilometer, the
change
length of the perimeter is only about 0.01 millimeter. This second
order
correction is clearly negligible. Of course, for a large eccentricity,
the corrections imply other corrections due to the principle of
mass-energy
conservation. However, they are irrelevant here but they have been
taken
into account later in this paper in equation 78 and in the original
paper
on the subject
[1].
This
conclusion
is also very important because in section 10 we had to calculate the
perimeter
of an ellipse having a small eccentricity (a first order series
expansion).
Consequently, we see now that the first order series expansion contains
no first power term. Therefore in that case, the perimeter of the
ellipse
with a small eccentricity is equal to the circumference of the circle.
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13- References.
[1A]
Die
Räumliche und zeitliche Ausbreitung der Gravitation. Von
Paul
Gerber. Zeitschrift für Mathematik und Physik Vol.
43,
Pages
93-104
(1898).
Also:
Paul
Gerber,
Die Fortplfanzungsgeschwindigkeit der Gravitation, Annalem
der Physik, Vol 52, p. 415-444, 1917 (*)
[1] P. Marmet, "Einstein's
Theory of Relativity versus Classical Mechanics", Ed. Newton
Physics
Books, 200 pages (1997), 2401 Ogilvie Rd. Gloucester, On. Canada, K1J
7N4,
also on the internet at the address: http://www.newtonphysics.on.ca/EINSTEIN/index.html
[2] R. P. Feynman, The Feynman
Lectures
on Physics, Vol. 1, chapter 21, Addison-Wesley Pub, Co. 1963.
[3] P. Rowland, "Newton and the
Concept
of Mass-Energy" Department of History, University of Liverpool,
Liverpool
University Press, P.O. Box 147, Liverpool, L69 3BX (1990).
[4] Meta Research Bulletin,
Editor's
note, 3, 1 (11) 1994, P.O. Box 15186, Chevy Chase, MD,
20825-5186,
USA.
[5] R. Brink, Analytical Geometry,
Ed. D. Appleton-Century Company Inc. New York, P. 217 (1935).
[6] P. Marmet, "Absurdities
in Modern Physics: A Solution" (1993), Ed. Les Editions du Nordir,
c/o R. Yergeau, 165 Waller St. Simard Hall, Ottawa, On. Canada K1N 6N5.
[7] Sagnac, M. G. J. de Phys.
1914, 4, 177-195.
[8] A. G. Kelly, "The Sagnac Effect
and GPS Synchronisation of Clock-Stations" International Meeting: Galileo
Back
in
Italy, Bologna, Italy, May 26-29 1999.
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If you read this paper after chapter six of the Book: Einstein's
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you return to chapter seven at: Chapter
Seven
About the Author
Contact e-mail
address.
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This paper on the Web is a
revised
and corrected version of the original paper.
---
This paper has been published under the title: "Classical
Description
of
the Advance of the Perihelion of Mercury" in
Physics
Essays
Volume 12, No: 3, 1999, P. 468-487.
---
This paper has been presented at the International
Meeting:
"Galileo Back in Italy II" Bologna Italy, 26-30 May 1999,
Title: "Einstein's Mercury Problem Solved in Galileo's
Coordinates" .. This paper is printed in the proceedings: "Galileo
Back
in
Italy" Istituto di Chimica, "G. Ciamician", Via
Selmi
2 - Bologna, Italy. P. 352 to 359.
---
This paper has also been presented as an invited
speaker
at the meeting of the Society for Scientific Exploration at
Albuquerque,
June 3-5, 1999. The title is: "A Logical and Understandable
Explanation to the Advance of the Perihelion of Mercury"
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